Question

如右圖放置的正方形ABCD，AB＝1，A，D分別在x軸、y軸的正半軸(含原點)上滑動，則的最大值是________．

 

 

Answer 1

2

【解析】令∠OAD＝θ，∵AD＝1，∴OA＝cos θ，OD＝sin θ，∠BAx＝－θ，故xB＝cos θ＋cos ＝cos θ＋sin θ，yB＝sin ＝cos θ，∴＝(cos θ＋sin θ，cos θ)，同理可求得C(sin θ，cos θ＋sin θ)，∴＝(sin θ，cos θ＋sin θ)，∴＝(cos θ＋sin θ，cos θ)·(sin θ，cos θ＋sin θ)＝1＋sin 2θ≤2.